Vector A makes equal angle with x,y,z axis .value of its component in form of magnitude of vector a will be
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Let vector A=xi+yi+zk make a, b, c angle with x, y, z axis respectively.
Then we know
cos(a) =x/|A|
cos(b) =y/|A|
cos(c) =z/|A|
Here a=b=c so we get
x=y=z
Let x=y=z= k(any constant)
Thus A=K(i+j+k)
Another formula of vector angels is
{cos(a)}^2 +{cos(b)} ^2 +{cos(c)} ^2=1
Or, 3{cos(a)}^2=1 as a=b=c
Or, cos(a) =1/√3=cos(b) =cos(c)
So the components are
x=|A|cos(a) =|A|/√3
y=|A|cos(b) =|A|/√3
z=|A|cos(c) =|A|/√3
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