Veena’s mother gave her Rs. 2 xy2and her father gave her Rs. 7 (xy2+ 3). She spent Rs (3 + 4 xy2) on her shopping. Algebraically how much money is left with her?
Answers
Step-by-step explanation:
Given Veena’s mother gave her Rs. 2 xy2 and her father gave her Rs. 7 (xy2+ 3). She spent Rs (3 + 4 xy2) on her shopping. Algebraically how much money
Given Veena’s mother gave Rs 2 xy^2, her father gave her Rs 7 (xy^2 + 3).
So it will be 2xy^2 + 7(xy^2 + 3)
She spent Rs (3 + 4xy^2) on her shopping. So we need to find out the money left with her.
So we get 2xy^2 + 7(xy^2 + 3) - (3 + 4xy^2)
2xy^2 + 7xy^2 + 21 – 3 – 4xy^2
5xy^2 + 18 will be the amount left with her algebraically.
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Amount of money left with Veena is
Rs (5xy² + 18)
Step-by-step explanation:
Given,
Amount of money mother gave to Veena = Rs 2xy²
Amount of money father gave to Veena = Rs 7 (xy² + 3)
Amount of money Veena spent = Rs (3 + 4xy²)
Total amount of Veena got from mother and father = Rs 2xy² + Rs 7 (xy² + 3)
⇒ 2xy² + 7 (xy² + 3)
⇒ 2xy² + 7xy² + 21
⇒ Rs (9xy² + 21)
Amount of money left with Veena = Total amount - Money spent
⇒ Rs (9xy² + 21) - Rs (3 + 4xy²)
⇒ (9xy² + 21) - (3 + 4xy²)
⇒ 9xy² + 21 - 3 - 4xy²
⇒ 9xy² - 4xy² + 21 - 3
⇒ 5xy² + 18
⇒ Rs (5xy² + 18)
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