Question

Velocity is given by v = 4t(1 2t) then find time at which velocity is maximum.

Answer 1

Answer:

v=4t−8t

2

For finding v_{max} :

dt

dv

=0

4−16t=0

t=1/4

checking

dt

2

d

2

v

sign

dt

2

d

2

v

=−16⇒maxima at t=1/4

t=0.25sec