Question

Velocity of a ball of 25 g load 6.6 x 10^4 cm / sec, then de Broglie wavelength is known. .​

Answer 1

Answer:

$\large \text{de Broglie wavelength = \lambda=4.01\times10^{-35} \ m }$

Explanation:

Given :

Mass = 25 g = 0.025 k g

$\large velocity=6.6\times10^4 \ cm/sec\\\\\\\large velocity=6.6\times10^2 \ m/sec$

We know de Broglie wavelength equation

$\large \lambda=\dfrac{h}{mv}$

where   λ = wavelength

m = mass

v = velocity

h = planck constant  

$\large planck \ constant \ value=6.626\times10^{-34} \ J \ sec$

Now put values in equation

$\large \text{ \lambda=\dfrac{6.626\times10^{-34}}{0.025\times6.6\times10^2} \ m }\\\\\\\large \text{ \lambda=\dfrac{\cancel 6.626\times10^{-34}}{\cancel 16.5} \ m }\\\\\\\large \lambda=0.401\times10^{-34} \ m\\\\\\\large \lambda=4.01\times10^{-35} \ m$

Thus we get answer.

Answer 2

Answer:

De Broglie wavelength = $\lambda = 4.01 \times\ 10^-^3^5m$

Explanation:

Given Problem:

Velocity of a ball of 25 g load 6.6 x 10^4 cm / sec, then de Broglie wavelength is known.

Solution:

To Find:

De Broglie wavelength.

---------------------

Method:

According to your question:

Mass = 25 g = 0.025 k g

$Velocity = 6.6 \times10^4cm/sec$

$Velocity = 6.6 \times10^2 m/sec$

We know that,

De Broglie wavelength equation:

$\lambda = \dfrac{h}{mv}$

Here:

λ = wavelength  

m = mass

v = velocity  

h = planck constant  

Planck costant = $6.626 \times10^-^3^4 J sec$

Now,

Put Values in equation,

$\lambda = \dfrac{6.626\times 106^-^3^4}{0.025\times 6.6\times\ 10^2}\:m$

$\lambda = \dfrac{6.626 \times10^-^3^4}{16.5}\: m$

$\lambda = 0.401 \times 10^-^3^4$

$\lambda = 4.01 \times 10^-^3^5.........(Answer)$