Question

Velocity of a body changes from 20 m/s to 40 m/s in 10 seconds. What is the distance

travelled in this 10 seconds?​

Answer 1

Answer:

initial velocity (u) =20m/s

final velocity (v) =40m/s

time (t) =10 s

acceleration (a) =v-u/t

=40-20/10

2m/s^2

distance(s)=?

v^2-u^2=2as

(40)^2-(20)^2=2(2)(s)

1600-400=4s

s = 1200/4

s = 300 m

Answer 2

Given :-

• Velocity of a body changes from 20 m/s to 40 m/s in 10 seconds.

To find :-

• Distance travelled in this 10 seconds

Solution :-

• Initial velocity = 20m/s

• Final velocity = 40m/s

• Time taken = 10s

According to first equation of motion

→ v = u + at

Where " v " is final velocity, " u " is initial velocity, " a " is acceleration and " t " is time.

Put the values

→ 40 = 20 + a × 10

→ 40 - 20 = 10a

→ 20 = 10a

→ a = 20/10

→ a = 2m/s²

Hence, acceleration of body is 2m/s²

According to second equation of motion

→ s = ut + ½ at²

→ s = 20 × 10 + ½ × 2 × (10)²

→ s = 200 + 100

→ s = 300m

Hence,

• Distance travelled by body is 300m