Physics, asked by shaktisinghshekhawat, 7 months ago

Velocity of a body falling freely depends on g and h, where g is acceleration due to gravity and h is the height through which the body has fallen. Derive an expression for velocity.

Answers

Answered by dp14380dinesh
2

Answer:

11th

Physics

Units and Measurement

Dimensions and Dimensional Analysis

The velocity of a body fall...

PHYSICS

The velocity of a body falling under gravity is directly proportional to g

a

h

b

. If g and h are the acceleration due to gravity and height covered by the body, respectively, then determine the values of a and b.

December 20, 2019

avatar

Nirajana Rathi

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ANSWER

We know, one of the fundamental equation of motion is

v

2

−u

2

=2as

Where, v is Final Velocity

u is Initial Velocity

a is Acceleration

t is time taken.

In case of motion under gravity, the acceleration a and the distance s in the above equations are replaced by gravity g and the height of the object.

Thus the acceleration due to gravity equation is,

v

2

−u

2

=2gh

Where,

h is Height from ground level and

g is acceleration due to gravity.

For a body falling under gravity initially at rest i.e. u = 0, hence

v

2

=2gh

v=

2

gh

⇒v∝

g

h

⇒v∝g

2

1

h

2

1

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Answered by vkpathak2671
1

Answer:

11th

Physics

Units and Measurement

Dimensions and Dimensional Analysis

The velocity of a body fall...

PHYSICS

The velocity of a body falling under gravity is directly proportional to g

a

h

b

. If g and h are the acceleration due to gravity and height covered by the body, respectively, then determine the values of a and b.

December 20, 2019

avatar

Nirajana Rathi

Share

Save

ANSWER

We know, one of the fundamental equation of motion is

v

2

−u

2

=2as

Where, v is Final Velocity

u is Initial Velocity

a is Acceleration

t is time taken.

In case of motion under gravity, the acceleration a and the distance s in the above equations are replaced by gravity g and the height of the object.

Thus the acceleration due to gravity equation is,

v

2

−u

2

=2gh

Where,

h is Height from ground level and

g is acceleration due to gravity.

For a body falling under gravity initially at rest i.e. u = 0, hence

v

2

=2gh

v=

2

gh

⇒v∝

g

h

⇒v∝g

2

1

h

2

1

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