Physics, asked by soniyachoudhary1245, 7 months ago

velocity of a cyclist increase from 5m/sec to 25m/sec in 10sec it's acceleration is​

Answers

Answered by BrainlyShadow01
25

\huge\fcolorbox{red}{h}{Question}

Velocity of a cyclist increase from 5m/sec to 25m/sec in 10sec it's acceleration is.

\huge\fcolorbox{red}{yellw}{Given}

  • The initial velocity of cycle is 5m/s.
  • The final velocity of cycle is 25m/s.
  • time taken is 10sec.

\huge\fcolorbox{red}{yellw}{Formulas}

  • v = u + at
  • v² - u² = 2as
  • s = ut + 1/2 at²

\huge\fcolorbox{red}{yello}{Solution}

u = 5m/s ;v = 25m/s ; t = 5sec ; a = ?

➣ v = u + at

➣ 25 = 5 + 5a

➣ 25 - 5 = 5a

➣ 20 = 5a

➣ a = 20/5

➣ a = 4m/s²

( Or )

➣ a = (v - u)/t

➣ a = (25 - 5)/5

➣ a = 20/5

➣ a = 4m/s²

Answered by ItsUDIT
301

Explanation:

\huge\fcolorbox{blue}{green}{Given}

  • The initial velocity of cycle is 5m/s.

  • The final velocity of cycle is 25m/s.

  • time taken by cyclists is 10sec.

\huge\fcolorbox{blue}{green}{Formulas used}

  • v = u + at

  • v² - u² = 2as

  • s = ut + 1/2 at²

\huge\fcolorbox{blue}{green}{Solution}

➣ a = (v - u)/t

➣ a = (25 - 5)/10

➣ a = 20/10

➣ a = 2m/s²

( Or ) IT CAN BE:

u = 5m/s ; v = 25m/s ; t = 10sec ; a = ?

➣ v = u + at

➣ 25 = 5 + 10a

➣ 25 - 5 = 10a

➣ 20 = 10a

➣ a = 20/10

➣ a = 2m/s²

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