velocity of a cyclist increase from 5m/sec to 25m/sec in 10sec it's acceleration is
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Velocity of a cyclist increase from 5m/sec to 25m/sec in 10sec it's acceleration is.
- The initial velocity of cycle is 5m/s.
- The final velocity of cycle is 25m/s.
- time taken is 10sec.
- v = u + at
- v² - u² = 2as
- s = ut + 1/2 at²
u = 5m/s ;v = 25m/s ; t = 5sec ; a = ?
➣ v = u + at
➣ 25 = 5 + 5a
➣ 25 - 5 = 5a
➣ 20 = 5a
➣ a = 20/5
➣ a = 4m/s²
( Or )
➣ a = (v - u)/t
➣ a = (25 - 5)/5
➣ a = 20/5
➣ a = 4m/s²
Answered by
301
Explanation:
- The initial velocity of cycle is 5m/s.
- The final velocity of cycle is 25m/s.
- time taken by cyclists is 10sec.
- v = u + at
- v² - u² = 2as
- s = ut + 1/2 at²
➣ a = (v - u)/t
➣ a = (25 - 5)/10
➣ a = 20/10
➣ a = 2m/s²
( Or ) IT CAN BE:
u = 5m/s ; v = 25m/s ; t = 10sec ; a = ?
➣ v = u + at
➣ 25 = 5 + 10a
➣ 25 - 5 = 10a
➣ 20 = 10a
➣ a = 20/10
➣ a = 2m/s²
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