Question

velocity of a particle given by v=3t*² + 2t*2m/s find it's average velocity between t=0 to t=3 and also find it's acceleration at t=3​

Answer 1

at t=0 s

v = 0 m/s

at t=3s

v = 3(3)^2 + 2(3)^2 = 27 + 18 = 45 m/s.

avg . velocity =【velocity {t=0} + velocity {t=3}】/2

= 【0+45 】/2 = 22.5 m/s.

acceleration = dv/dt = (d/dt)(3t^2 + 2t^2) = 6t + 4t

as t=3 ,. acceleration = 6×3 + 4×3 = 30 m/s^2.