Question

velocity of a particle with respect to position is given as v = x+2 . find acceleration at 1m position ​

Answer 1

Answer:

a=(x+2)/60

Explanation:

v=u+at

given v=x+2

t=1m=60sec

u=0( initial velocity)

x+2=0+60a

a=(x+2)/60

Answer 2

Answer:

a=dv/dt=d/dt(x+2)

=1×^0+0

=1

☆a=1m/s^2

(conatant acceleration)