Question

Velocity of a train changes from 20m/s to 25
m/s, when it accelerate at a rate 2 m/s2. Find the
distance covered by the train​

Answer 1

v2-u2=2as

=25^2-20^2=2*2s

=625-400=4s

=225/4=s

=s=56.25m

Voila

Answer 2

Answer:

Explanation:

We know that the formula

v2 =u2 + 2as

Where we know V is the final velocity

And U is the initial velocity

The value of V final velocity is = 25m/ s

The value of U intial velocity is = 20 m/ s

Now the acceleration is =2m/ s square

And the distance travelled is S

Then we substitute the value of above equation of motion to get

S = (625- 400) /4

S = 56.25