Question

Velocity of an object at t=0 is v =4jm/s it moves in constant acceleration a=3i+8jm/s^2. What is the velocity after 1s ?

Answer 1

u= 4j m/s
t= 1 sec
a = 3i+8j m/s^2

v= ?

v= u+at

v= 4j + 3i+8j= 3i+ 12j m/s

Answer 2

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Question:
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The velocity of an object at t=0 is v=-4j m/s it moves in a plane with constant acceleration a=3i+8jm/s^2 what is its velocity after 1s.

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Answer:
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Using equation of motion:

V = u + at

We have,

Writing the equation of motion in vector form.

a = (3i+ 8j) m/s^2

v= -4j + (3i+ 8j)1 as u =  -4j m/s and t=1 sec 

or , v= 3i+ 4j

​So final velocity = (3^2 + 4^2)^1/2 = 5m/s