Question

velocity of sound in a gaseous mediym is 330ms^-1.if the pressure is increased by 4 times without causing change in the temperature the velocity of sound in the gas is​

Answer 1

answer : no change in velocity of sound in the gas .i.e., velocity of sound in the gaseous medium is 330m/s.

explanation : we know, velocity of sound is given by, $v=\sqrt{\frac{\gamma P}{\rho}}$.......(1)

where $\gamma$ is atomicity of gaseous medium, P is pressure of gas and ρ is density of gas.

from formula of density, ρ = PM/RT

or, P/ρ = RT/M

here given, temperature remains constant.i.e., T = constant

so, P/ρ = RT/M = constant .......(2)

from equations (1) and (2), it is clear that velocity of sound remains constant.

hence, velocity of sound = 330m/s.

[ note : you should know, $\gamma$ is a constant term for a specific gas ]

Answer 2

Answer:

Explanation:v is inversley propostional to sqyare root of p .so 330/v2=2p/p after removing square..so answer is 165ms^-1