Math, asked by Quenniestdynamo07, 7 hours ago

Velocity of the object of mass 10 kg increases from 18 m/s to 36 m/s. A constant force acts on the object for 2 seconds. Find its force. What will be the force for time 4 seconds?​

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Answers

Answered by anshmishradps09
0

Answer:

Mass of the body =10 kg

Initial velocity u=4 m/s

Final velocity v=8 m/s

Time t=2s

a) Momentum before force acts p

1

=m×u=10×4=40kg.m/s

b) Momentum after force acts p

2

=m×v=10×8=80kg.m/s

c) Gain in momentum per second =

2

40

=20kg.m/s

d) Acceleration a=

t

v−u

=

8−4

=2m/s

2

Force =m×a=10×2=20 N

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