velocity of waves along a string is v= √ T/m,Where 'T' the tension in the string and 'm' is mass per unit length of the string.Show this quation is dimentionaly correct
Answers
Answered by
57
Answer:
Given:
Equation for velocity of wave in string has been given.
To find:
Whether this Equation is dimensionally correct or not.
Calculation:
Dimensional analysis is performed by matching the LHS AND RHS.
LHS
Velocity has the following dimension:
V = [ L T^(-1) ] ..........(1)
RHS
√(T/m) ,
where T => Tension and m => mass per unit length
Tensions is actually force ,
Mass per unit length can be represented as M/L
Continuing with the Calculation:
√(T/m)
= √ [ {M L T^(-2)}/ { M L^(-1)} ]
= √[ L² T^(-2)]
= L T^(-1) .........(2)
Since (1) = (2) , we have LHS = RHS.
Hence the Equation I dimensionally correct.
Answered by
34
Answer:
velocity of wave = √T/m
m =>mass per unit length
T is tensile force
Dimension of T => ML T^-2
Dimension of m => M L^-1
Velocity dimension = √[(MLT^-2)/ML^-1]
= √(L^2 T^-2)
= L T^-1
Which is dimension of velocity
hence eq is dimensionally correct
#answerwithquality #BAL
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