Question

velocity time graph of a body moving with uniform positive acceleration​

Answer 1

Explanation:

This the graph of the following question

Answer 2

Explanation:

1. When the body is moving with uniform velocity

If the object moves at uniform velocity, the height of its velocity-time graph will not

change with time. It will be a straight line parallel to the x-axis. We know that the product

of velocity and time give displacement of an object moving with uniform velocity. The area

enclosed by velocity-time graph and the time axis will be equal to the magnitude of the

displacement.

To know the distance moved by the car between time t1 and t2 using the above figure, draw

perpendiculars from the points corresponding to the time t1 and t2 on the graph. The

velocity of v km/h is represented by the height AC or BD and the time (t2 – t1) is

represented by the length AB. So, the distance s moved by the car in time (t2 – t1) can be

expressed as

s = AC × CD = v(t2 – t1) = Area of the rectangle ABDC (shaded portion)

2. When the body is moving with uniform acceleration

In this case, the velocity-time graph for the motion of the car is shown in below figure. The

nature of the graph shows that velocity changes by equal amounts in equal intervals of

time. Thus, for all uniformly accelerated motion, the velocity-time graph is a straight line.