velocity v of a particle decrease linerialy with it's displacement s from 20m/s to a value approaching 0 at s=30m then acceleration of the particle at v=10m/s is
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Explanation:
Slope dsdv=30−20=3−2
∴ Slope 30−150−v∣∣∣∣∣s=15=3−2 ⟹v∣∣∣∣∣s=15=10m/s
Using a=vdsdv
∴ a∣∣∣∣∣s=15=v∣∣∣∣∣s=15×dsdv=10×3−2=3−20 m/s2
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