venky started working in 1995 at an annual salary 5000and received an increment of 200 each year in which year fid he get 7000salary?
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Answered by
0
in the year of 2005
The total increment in salary is 2000
total increment / annual increment = no of yrs.
2000/200 = 10 yrs more
1995 + 10 = 2005
The total increment in salary is 2000
total increment / annual increment = no of yrs.
2000/200 = 10 yrs more
1995 + 10 = 2005
Answered by
1
so this is a question of arithmetic progression
a=5000
& d=200
and the nth term =l=7000
l=a+(n-1)d
7000=5000+(n-1)200
7000-5000=(n-1)200
2000/200=n-1
10+1=n
n=11
so in 11years venky salary would be upto 7000
1995+11=2006
hence in 2006 he would get a salary of Rs.7000
a=5000
& d=200
and the nth term =l=7000
l=a+(n-1)d
7000=5000+(n-1)200
7000-5000=(n-1)200
2000/200=n-1
10+1=n
n=11
so in 11years venky salary would be upto 7000
1995+11=2006
hence in 2006 he would get a salary of Rs.7000
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