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An ideal gas expands isothermally from
10-3 m3 to 10-2 m3 at 300 K against a constant
pressure of 105 Nm-2. The work done on the gas is
[NEET-2019 (Odisha)]
(1) - 900 kJ
(2) + 270 kJ
(3) - 900 J
(4) + 900 kJ
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Answer:
:
Work done due to change in volume against constant pressure is
W = - p(V2-V1)
= - 1 x 105 Nm-2 (1 x 10-2- 1 x 10-3)m3
Work done due to change in volume against constant pressure is
W = - p(V2-V1)
= - 1 x 105 Nm-2 (1 x 10-2- 1 x 10-3)m3
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