verifu the relationship of the zeroes of the polynomial x2-10+x=0
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Answered by
0
Answer:
Let f(x)=x
2
+10x+16
The zero of the polynomial is given by f(x)=0
f(x)=0
=>x
2
+10x+16=0
=>x
2
+8x+2x+16=0
=>x(x+8)+2(x+8)=0
=>(x+8)(x+2)=0
Thus, x+8=0 and x+2=0
=>x=−8 and =>x=−2
Thus, zeros of the polynomial are −8,−2
Comparing f(x) with standard form of quadratic polynomial ax
2
+bx+c
Here, a=1, b=10, c=16
Sum of the zeros =−8+(−2)
=−10
=
a
−b
Product of the zeros =(−8)(−2)
=16
=
a
c
Answered by
2
Answer:
don't have time for explain it
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