Question

verify√1-cosA/√1+cosA=sinA/1+cosA,where A=60°

Answer 1

Hi ,

It is given that ,

A = 60°

cos60° = 1/2

Sin60° = √3/2

LHS = ( √ ( 1 - CosA )/√ ( 1 + cosA )

= √ ( 1 - cos60 )/√( 1 + cos60 )

= √ ( 1 - 1/2 ) / √ ( 1 + 1/2 )

= √ ( 1/2 )/√ ( 3/2 )

= 1/√3 ---( 1 )

RHS = sinA / ( 1 + cos A )

= Sin 60 / ( 1 + cos 60 )

= ( √3/2 ) / ( 1 + 1/2 )

= ( √3/2 ) / 3/2

= √3 / 3

= √3 / ( √3 × √3 )

= 1/√3 ---( 2 )

From ( 1 ) and ( 2 ) , we conclude that

LHS = RHS

I hope this helps you.

: )

Answer 2

Hi,

Please see the attached file!


Thanks