Question

verify (a-b)²=a²-2ab+b²​

Answer 1

Step-by-step explanation:

here a=3 and b=2.

L.H.S= (a-b)^2 = (3-2)^2= (1)^2 = 1

R.H.S= a²-2ab+b² = (3)² - (2*3*2) + (2)² = 9-12+4 = -3+4 = 1

so both the side, result is 1.

Hence L.H.S = R.H S it is proved.

Hope it answers your question. All the best!

Answer 2

Answer:

OBJECTIVE

To verify the identity (a-b)² = (a² – 2ab+b²)

Materials Required

1. A piece of cardboard
2. A sheet of glazed paper
3. A sheet of white paper
4. A pair of scissors
5. A geometry box

Procedure

We take distinct values of a and b.

Step 1: Paste the white paper on the cardboard. Draw a square ABCD of side a units.

Step 2: Calculate the value of (a – b). On the glazed paper, construct two rectangles each having length (a-b) units and breadth b units. Also, construct a square of side b units.

Step 3: Cut the square and the two rectangles from the glazed paper and place them on the white paper. Arrange these inside the square ABCD as shown in Figure 11.1.

Step 4: Label the diagram as shown in Figure 11.1. Record your observations.

Observations and Calculations

We observe that the area of square AEFH=(a-b)² square units.

Also, area of square AEFH

= area of square ABCD – area of rect. EBGF – area of rect. HFID – area of square FGCI

i. e., (a-b)² = a²-(a-b)b-(a-b)b-b²

=> (a-b)² =a²-ab+b²-ab+b²-b²

=> (a-b)² = (a² – 2ab+b²).

Result

The identity (a-b)² = (a² – 2ab+b²) is verified.