Question

verify (a+b)³=a³+b³+3a²b+3ab²​

Answer 1

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What is the formula for a³-b³?

Proof:

Proof:We know the well-known formula

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²a³ - b³ = (a-b)³ +3 ab(a-b)

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²a³ - b³ = (a-b)³ +3 ab(a-b)a³ - b³ = (a-b) [(a-b)² +3 ab]

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²a³ - b³ = (a-b)³ +3 ab(a-b)a³ - b³ = (a-b) [(a-b)² +3 ab]a³ - b³ = (a-b) [(a-b)² +3 ab]

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²a³ - b³ = (a-b)³ +3 ab(a-b)a³ - b³ = (a-b) [(a-b)² +3 ab]a³ - b³ = (a-b) [(a-b)² +3 ab]We all know (a - b)² = a² - 2 ab + b²

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²a³ - b³ = (a-b)³ +3 ab(a-b)a³ - b³ = (a-b) [(a-b)² +3 ab]a³ - b³ = (a-b) [(a-b)² +3 ab]We all know (a - b)² = a² - 2 ab + b²So

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²a³ - b³ = (a-b)³ +3 ab(a-b)a³ - b³ = (a-b) [(a-b)² +3 ab]a³ - b³ = (a-b) [(a-b)² +3 ab]We all know (a - b)² = a² - 2 ab + b²Soa³ - b³ = (a-b) [(a² - 2 ab + b²) +3 ab]

Proof:We know the well-known formula(a-b)³=a³-3 a²b+3 ab²-b³By transposition,a³ - b³ = (a-b)³ + 3 a²b - 3 ab²a³ - b³ = (a-b)³ +3 ab(a-b)a³ - b³ = (a-b) [(a-b)² +3 ab]a³ - b³ = (a-b) [(a-b)² +3 ab]We all know (a - b)² = a² - 2 ab + b²Soa³ - b³ = (a-b) [(a² - 2 ab + b²) +3 ab]a³-b³= (a-b)(a²+ab+ b²) [Proved]