verify a÷[b+c]≠[a÷b]+[a÷c] for the values a=-1,b=-1,c=-3
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Step-by-step explanation:
Given, a= -1, b= -1, c= -3
To prove: a÷(b+c) is not equal to (a÷b)+(a÷c )
Proof: LHS= a÷(b+c)
= -1÷(-1-3)
= -1/-4= 1/4
RHS= (a÷b)+(a÷c)
= (-1÷ -1)+(-1÷ -3)
= 1+1/3
= 4/3
LHS is not equal to RHS.
That is, a÷(b+c) is not equal to (a÷b)+(a÷c).
Hence, proved .
Hope it helps.
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