Question

Verify a×(b×c)=(a×b)×c for: a=27/43 ,b=0, c=-5/6​

Answer 1

Answer:

Step-by-step explanation:

a*(b*c)=(a*b)*c

27/43*(0*(-5/6))=(27/43*0)*(-5/6)

27/43*0=0*(-5/6)

0=0

Answer 2

Answer:

We have:

a × (b × c) = (a × b) × c

Put $a=\frac{27}{43}, b=0, c=\frac{-5}{6}$

$\frac{27}{43}$ × $(0$ × $\frac{-5}{6})$ = $\frac{27}{43}$ × $0=0$

$(\frac{27}{43}$ × $0)$ × $\frac{-5}{6}$ = $0$ × $\frac{-5}{6} = 0$