Question

Verify A(BC) = (AB)C in each of the
following cases.
[1 0 1
2
-2
1)
A= 12 3 0
, B = -1
1
and
0 4 5
0
3
3 2 -1
C=
2 0 - 2​

Answer 1

Answer:

hesbxhf c!zlaizhxbdyxnx. zjxnxhsk , xjs

Answer 2

Step-by-step explanation:

\huge \sf\underline\color{blue}{Given}\dag

Given†

If the mode of 5,3,3,2,2xis3.then find x

\huge \sf\underline\color{blue}{Solution}\dag

Solution†

Let’s represent the series in a different perspective,

Below are the positions,

Name Positions 1st 2nd 3rd

So, representation would be,

Positions

1 2 3 (Position's Alias/Naming)

1 5 8 = 76

2 7 3 = 25

3 4 9 = 89

4 5 7 = 69

5 3 8 = ?

Now, (by observation)

Take 1st and 3rd positions of each expression to make a number like this,

Number = 3rd position number (concatenate) 1st position number

e.g., if expression is 2 5 8 Then Number would be 82.

Then subtract 2nd position number from the Number would be 82 - 5 = 77.

Therefore,

By Observation,

5 3 8 = 85(Number) - 3 = 82

Answer = 82.

LETS TRY TO ANSWER THIS

FIRST OF ALL FIND THE LOGIC BEHIND IT

IF THE NUMBER ARE

Let a,b,c = d

Then c×10 -(b-a)=d

so now going by this logic we have

1,5,8=76

8×10-(5–1) =76

2,7,3=25

3×10 -(7–2)=25

3,4,9=89

9×10-(4–3)=89

4,5,7=69

7×10-(5–4)=69

So, 5,3,8=????

8×10-(3–5)=82

The answer is 82