Verify -cot^2xtanx = cot^2x-csc^2x/tanx
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Answer:
-cot^2×tanx = cot^2x-cos^2x/tanx
convert tan = sin / cos
cot = cos/sim
take LCM
verify.
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-cot^2×tanx = cot^2x-cos^2x/tanx
we know that tan = sin / cos -(trigonometric identity)
cot = cos/sin ---(as cot = inverse of tan which is sin/cos)
taking LCM
-( cos^2)/(sin^2) x sin/cos = ( cos^2)/(sin^2) - cos^2/(sin/cos)
-cos/sin = cos^2/sin^2 - cos^3/sin
multiplying by sin we get
-cos = cos^2/sin - cos^3
dividing by cos on both sides we get
-1 = cos/sin - cos^2
putting value of x as 90 to check
-1 = 0/1 - 0^2
-1=0
which is not possible, therefore this identity is not possible
CHEERS MATE, PLEASE MARK BRAINLIEST
verify.
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