Math, asked by monishamar30187400, 8 months ago

verify for zeros of polynomial p(x)=3x+1,x=-1/6​

Answers

Answered by DevyaniKhushi
1

 \huge{}p(x) = 3x + 1

Here,

 \huge \boxed{x =  \frac{ - 1}{6} }

Now, Putting the value of x in p(x), we get,

 =  >  3  \bigg\{ \frac{ - 1}{6} \bigg\}  + 1\\  \\   =  > \bigg \{\frac{3 \times  (- 1)}{6} \bigg \} + 1 \\  \\   =  >  \bigg(\frac{ - 1}{2}\bigg)  + 1 \\  \\ =  >   \:  \:  \:  \: \frac{ - 1 + 2}{2}  \\  \\  =  >  \:  \:  \:  \frac{1}{2}

Thus,

 \boxed{x =  \frac{ - 1}{6} } \:  \:  \tt{is \: \: not \:  \: the \:  \: solution \{ zeroes\}  } \\  \tt{of  \: \: the \:  \: equation \: p(x).}

Answered by shreeramya930
2

Answer:

Thank you monishamar

Step-by-step explanation:

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