Question

Verify if -2 and 3 are the zeroes of the polynomial 2x³-3x²-11x+6. If yes, factories it.

Answer 1

Hi friend,

Put x = -2

= 2(-2)³-3(-2)²-11(-2)+6

= 2(-8)-3(4)+22+6

= -16-12+22+6

= -28+28

= 0

-2 is a zero of the given polynomial.

Put x = 3

= 2(3)³-3(3)²-11(3)+6

= 2(27)-3(9)-33+6

= 54-27-33+6

= 60-60

= 0

3 is a zero of the given polynomial.

→ 2x³-3x²-11x+6

We know that (x+2) is a factor of the given polynomial as -2 is zero of the polynomial.

Divide the given polynomial by (x+2)

2x³-3x²-11x+6 ÷ (x+2)

= 2x² - 7x + 3

2x³-3x²-11x+6

→ (x+2)(2x²-7x+3)

→ (x+2)(2x²-6x-x+3)

→ (x+2){2x(x-3)-1(x-3)}

→ (x+2)(x-3)(2x-1)

Hope it helps

Answer 2

Answer:

Step-by-step explanation: