Question

Verify if x=2/root 3 and x=-2/3 are zero polynomials of g (x)=3xsquare-2

Answer 1

Answer:

Step-by-step explanation:

g(x) = $3x^{2} - 2$

x = $2\sqrt{3}$

g($2\sqrt{3}$) = $3(2\sqrt{3} )^{2} - 2$

           = 3(12) - 2

           = 36 - 2

           = 34

Since g(x) $\neq$ 0

Therefore $2\sqrt{3}$ is not a zero of g(x)

x = $\frac{-2}{3}$

g($\frac{-2}{3}$) = $3(\frac{-2}{3} )^{2} - 2$

         =  $3(\frac{4}{9}) -2$

          = $\frac{4}{3} - 2$

           =  $\frac{4 - 6}{3}$

         =  $\frac{-2}{3}$

Since g(x) $\neq$ 0

Therefore $\frac{-2}{3}$ is not a zero of g(x)