Question

verify if x+y+z=0 the prove x2 + y2 + z2 =3xyz

Answer 1

Answer:

Step-by-step explanation:

Given: x+y+z=0

To prove:x^2+y^2+z^2=3xyz

Proof : Apply the algebraic identity x^2+y^2+z^2-3xyz=(x+y+z) (x2 + y2 + z2 – xy – yz – zx).

= 0× (x2 + y2 + z2 – xy – yz – zx).

Therefore, x2+y2+z2-3xyz = 0

Therefore, x2+y2+z2=3xyz (transpositioning -3zyx to R.h.s hence became 3xyz)

Hope you understand..... pls mark me as the brainliest......