Math, asked by yormejumyiryorme, 11 months ago

verify of the identity (a_b)2=a2_2ab_b2​

Answers

Answered by Anonymous
1

Answer:

(a-b)2=a2-2ab+b2

(a-b)2=72-26×7+(6)2

49-2(42)+12

49-84+12

61-84

23

Step-by-step explanation:

this is the formula

Answered by pmvjs299
2

Answer:

(a-b)^2 = (a-b) * (a-b)

           = a^{2} -ab - ba + b^{2}

            = a^{2} - 2ab +b^{2}

for verification let take a = 5 and b = 3

(a - b)^2 = (5 - 3)^2

             = 4 ------------------------------ ( 1 )

now ,

a^{2} - 2ab +b^{2} = 5^2 - 2(5)(3) + 3^2

                     = 25 - 30 + 9

                     = 4 ------------------------------- ( 2 )

from ( 1 ) and ( 2 )  (a - b)^{2} =  a^{2} - 2ab +b^{2}

hope it helps !

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