Question

verify: p(x) =x^2-1,x=1,-1 is zeroes of polynomial​

Answer 1

Answer:

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Answer 2

$p(x) = {x}^{2} - 1,\: x = - 1,1 \\ p(x) = {( - 1)}^{2} - 1 \\ p(x) = 1 - 1 \\ p(x) = 0$

$p(x) = {x}^{2} - 1 \\ p(x) = {1}^{2} - 1 \\ p(x) = 0$