Verify taht 1,2,3are zeros of the polynomial y³-6y²+11y-6.
Answers
Answered by
8
Answer:
1,2,3are zeores
Step-by-step explanation:
puty=1
(1)^3-6(1)^2+11(1)-6
1-6+11-6
12-12
=0
put y=2
(2)^3-6(1)^2+11(2)-6
8-24+22-6
-30+30
=0
put y=3
(3)^3-6(3)^2+11(3)-6
27-54+33-6
60-60
=0
Answered by
1
Answer:
see this and do it very easy way to solve it
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