Question

Verify:
$\frac{1}{2}$ ÷ [ $\frac{-1}{3}$ ÷ $\frac{2}{5}$ = [ $\frac{1}{2}$ ÷ ( $\frac{-1}{3}$ ] ÷ $\frac{2}{5}$

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Answer 1

Answer:

$\frac{1}{2} \div ( \frac{ - 1}{3} \div \frac{2}{5} ) = ( \frac{1}{2} \div \frac{ - 1}{3} ) \div \frac{2}{5} \\ \frac{1}{2} \div ( \frac{ - 1}{3} \times \frac{5}{2} ) = ( \frac{1}{2} \times \frac{3}{ - 1} ) \div \frac{2}{5} \\ \frac{1}{2} \div \frac{ - 5}{6} = \frac{3}{ - 2} \div \frac{2}{5} \\ \frac{1}{ _{1 \: \: \: } \cancel 2} \times \frac{ \cancel 6_{ \: \: \: 3} }{ - 5} = \frac{3}{ - 2} \times \frac{5}{2} \\ \boxed{ \underline{ \underline{ \large \bf \frac{3}{ - 5} ≠ \frac{15}{ - 4} }}}$