verify that 0and 3 are the zero of p (x) = x3-3x
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Answered by
1
Hey user !!
Here is your answer !!
____________________________________________⭐
For verification
Put value of the zeroes in
p(x)=x^3-3x
p(0) = (0)^3 -3(0)
= 0
Now,
p(x) = x^3 - 3x
p(3) = (3)^3 -3(3)
=27-9=18
so 3 is not a zero of polynomial
Hence verified
Hope it is satisfactory :-)
_________________________________________⭐
Here is your answer !!
____________________________________________⭐
For verification
Put value of the zeroes in
p(x)=x^3-3x
p(0) = (0)^3 -3(0)
= 0
Now,
p(x) = x^3 - 3x
p(3) = (3)^3 -3(3)
=27-9=18
so 3 is not a zero of polynomial
Hence verified
Hope it is satisfactory :-)
_________________________________________⭐
saijahnavi:
its wrong answer
Answered by
1
for verifying
we put x=0 in x3-3x
p(0) = (0)3. - 3×(0)
=0
we put x=3 in x3-3x
p(3) = (3)3 - 3×3
= 27-9=18
x=0 is the zero of p(x)
we put x=0 in x3-3x
p(0) = (0)3. - 3×(0)
=0
we put x=3 in x3-3x
p(3) = (3)3 - 3×3
= 27-9=18
x=0 is the zero of p(x)
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