write the trigonometric ratios sin A ,sec A, tanA in terms of cot A
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sinA=1/cosecA=1/√1+cot^2A
secA=√1+tan^2A=√1+1/cot^2A=√cot^2A+1/cotA
tanA= 1/cotA
secA=√1+tan^2A=√1+1/cot^2A=√cot^2A+1/cotA
tanA= 1/cotA
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Hiii. .....friend
the answer is here,
:-)Hope it helps u.
the answer is here,
:-)Hope it helps u.
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