Math, asked by saijahnavi, 1 year ago

write the trigonometric ratios sin A ,sec A, tanA in terms of cot A

Answers

Answered by VikasKaran
2
sinA=1/cosecA=1/√1+cot^2A
secA=√1+tan^2A=√1+1/cot^2A=√cot^2A+1/cotA
tanA= 1/cotA
Answered by jaya1012
4
Hiii. .....friend

the answer is here,

 \sin(a)  =  \frac{1}{ \sqrt{1 +  {cot}^{2}a } }

 =  >  \:  \sec(a)  =  \sqrt{ \frac{1 +  {cot}^{2}a }{ {cot}^{2} a} }

 =  >  \:  \tan(a)  =  \frac{1}{ \cot(a) }

:-)Hope it helps u.
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