verify that 1,-1,-3 are the zeroes of the cubic polynomial x cube+3x square - x-3 and check the relationship between zeros and coefficients
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Put x=1 in x^3+3x^2-x-3
1+3-1-3 =0
Now put x=-1 -1 +3+1-3 =0
Now put x=-3
-27 +27 +3-3 =0
I hope this will help you
1+3-1-3 =0
Now put x=-1 -1 +3+1-3 =0
Now put x=-3
-27 +27 +3-3 =0
I hope this will help you
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