Question

verify that : -1/2+((-4/3)+3/7=((-1/2)+3/7)+(-4/3)​

Answer 1

Hiii frnd...

LHS = -1/2 (-4/3 +3/7)

= -1/2 (-28+9/21)

= -1/2(-19/21)

= -21-38/42

= -59/42

RHS. = (-1/2 +3/7) -4/3

=(-7+6/14) -4/3

=-1/14 -4/3

=-3-56/42

= -59/42

Lhs = rhs

Hope it helps......

Answer 2

Answer:

$\frac{-1}{2} + (\frac{-4}{3} ) + \frac{3}{7} = (\frac{-1}{2})+\frac{3}{7}) + (\frac{-4}{3} )$ verified.

Step-by-step explanation:

Explanation:

Given in the question that, $\frac{-1}{2} + (\frac{-4}{3} ) + \frac{3}{7} = (\frac{-1}{2})+\frac{3}{7}) + (\frac{-4}{3} )$

Now, we need to verify that LHS = RHS.

So, first, we solve LHS than RHS.

Step 1:

From the question we have,

LHS = $\frac{-1}{2} + (\frac{-4}{3} ) + \frac{3}{7}$

LCM of 2 , 3 and 7 = 2× 3 ×7 = 42

⇒$\frac{-21 -4(14) + 3(6)}{42}$ = $\frac{-21 -56 + 18}{42}$

⇒ $\frac{-77 + 18}{42}$ = $\frac{-59}{42}$

Now, we  solve RHS

So, from the question RHS = $(\frac{-1}{2}+\frac{3}{7}) + (\frac{-4}{3} )$

LCM of 2, 3, and 7 = 2 × 3 ×7  = 42

⇒ $\frac{-21+3(6)+(-4)14}{42}$ = $\frac{-21+ 18+(-56)}{42}$

⇒ $\frac{-77 + 18}{42}$ = $\frac{-59}{42}$

So, here we proved that LHS = RHS = $\frac{-59}{42}$.

Final answer:

Hence, $\frac{-1}{2} + (\frac{-4}{3} ) + \frac{3}{7} = (\frac{-1}{2})+\frac{3}{7}) + (\frac{-4}{3} )$ verified.

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