Verify that 2 and (-3) are zeroes of the polynomial p(x)=(x-2)(x+3).
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Answer:(i) p(x) = 3x + 1, x = - 1/3
(ii) p(x) = 5x – π, x = 4/5
(iii) p(x) = x2 – 1, x = 1, –1
(iv) p(x) = (x + 1) (x – 2), x = – 1, 2
(v) p(x) = x2, x = 0
(vi) p(x) = lx + m, x = –m/l
(vii) p(x) = 3x2 – 1, x = - 1/√3 , 2/√3
(viii) p(x) = 2x + 1, x =1/2
Step-by-step explanation:
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