verify that 3,-1,1/3 are the zeroes of the cubic polynomials.p(x)=3x^3-5x^2-11x-3
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Answer:
p(3)=3(3)^3-5(3)^2-11(3)-3
=3(27)-5(9)-33-3
=81-45-33-3
=0
p(-1)=3(-1)^3-5(-1)^2-11(-1)-3
=3(-1)-5+11-3
=-3-5+11-3
=0
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