Verify that 3 is the zero of the cubic polynomial p(x) = 3x^3-5x^2-11x-3
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Answered by
4
if 3 is a zero of the polynomial p(x),
then p(3) will be equal to zero.
then
p(3)=3×(3)³-5×(3)²-11×3-3,
p(3)=3×27-5×9-33-3,
p(3)=81-45-36,
p(3)=81-81,
p(3)=0,
since
p(3)=0,
therefore
3 is a zero of the polynomial.
then p(3) will be equal to zero.
then
p(3)=3×(3)³-5×(3)²-11×3-3,
p(3)=3×27-5×9-33-3,
p(3)=81-45-36,
p(3)=81-81,
p(3)=0,
since
p(3)=0,
therefore
3 is a zero of the polynomial.
Answered by
1
Hey mate, here is your answer -:)
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

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HOPE it helps to you!!!
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HOPE it helps to you!!!
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