Question

Verify that a ÷ b # b ÷ a for the following value of a and b. +36 = a , b = 6

Answer 1

Answer:

(i) a = 21, b = 18

a – (-b) = 21-(-18)

21-(-18) = 21 + 18

21+18= 39

a + b = 21+18

21+18 = 39

21-(-18) = 21+18 = 39

(ii) a = 118, b = 125

a – (-b) = 118 – (- 125)

118- (- 125) = 118 + 125 = 243

a + b = 118 + 125

118 + 125 = 243

118 – (- 125) = 118 + 125 = 243

(iii) a = 75, b = 84

a – (-b) = 75 – (- 84)

75 – (- 84) = 75 + 84 =159

a + b = 75 + 84

75 + 84 =159

75 – (- 84) = 75 + 84 =159

(iv) a = 28, b = 11

a – (-b) = 28 – (-11)

28 – (-11) = 28 + 11 = 39

a + b = 28 + 11= 39

28 +11= 39

28 – (-11) = 28 +11= 39

Answer 2

Given to verify :-

${a\div b \neq b\div a}$

• a = 36
• b = 6

Solution:-

We shall take LHS

$a \div b$

$36 \div 6$

$= \dfrac{36}{6}$

$= 6$

So, LHS = 6

We shall take RHS

${b\div a}$

$6 \div 36$

$\dfrac{6}{36}$

$\dfrac{1}{6}$

RHS = 1/6

${6 \neq 1/6}$

${LHS \neq RHS}$

${a\div b \neq b\div a}$

Hence proved!_________________

Know more :-

Commutative property :-

It only statisfies for multiplication and addition It doesn't satisfies for division and subtraction

If we change the order of number Its value remains same .

For addition ,

a + b = b + a

For multiplication,

ab = ba

For subtraction,

a - b ≠ b - a

For division

a÷ b ≠ b÷ a