Verify that the function y = a cos x + b sin x, where, a, b ∈ R is a solution of the differential equation d2y/dx2 + y=0...
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Y= a cosx + b sinx
dy/dx = - a sinx +b cosx
d2y/dx2= - a cos x - b sinx
LHS
d2y/dx= - a cosx - b sinx
LHS =d2y/dx2 +y
=. - a cosx - b sinx +a cosx + b sinx
=0
= RHS
HENCE, Verified
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