Math, asked by sanjana28006, 6 months ago

verify that the number given alongside of the cubic polynomial below are their zeroes also verify the relationship between the zeroes and the coefficient in each case 1. 2x³+x²-5x+2;1/2, 1,-2​

Answers

Answered by chandbhalodia2005
4

Answer:

I hope my answer will help you.

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Answered by winterrnightz
0

Answer:

Step-by-step explanation:

Given,

p(x) : 2x³ + x² - 5x + 2

If 1/2 is a zero of p(x), Then, p(1/2) should be zero.

p(1/2) = 2×(1/2)³ + (1/2)² -5×(1/2) + 2

= 2×(1/8) + 1/4 - 5/2 + 2

= 1/4 +1/4  - 5/2 + 2

= 2/4  -5/2 + 2

= 1/2 - 5/2 + 2

= -4/2 + 2

= -2 + 2

= 0

Hence, 1/2 is a zero of given polynomial

Similarly,

p(1) = 2×(1)³ + 1² -5×1 + 2

=2 + 1 - 5 + 2

= 3 - 5 + 2

= 2

And,

p(-2)  = 2×(-2)³ + (-2)² -5(-2) + 2

= -2×8 + 4 + 10 + 2

= -16 + 14 + 2

= -2 + 2

= 0

Hence, 1 and -2 are also zeroes of given polynomial

Now, We have to verify relations between zeroes:-

Comparing given polynomial with standard form of equation of 3rd degree,

ax³ + bx + c + d

a = 2

b = 1

c = -5

d = 2

Sum of zeroes  = -b/a

1/2 + 1 + (-2) =  -1/2

1/2 - 1 = -1/2

-1/2 = -1/2

L.H.S. = R.H.S.

Product of zeroes = d/a

1/2 × 1 × (2) = 2/2

1 = 1

L.H.S. = R.H.S.

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