Verify that the numbers given alongside the cubic polynomials below are their zeroes.
Also verify the relationship between the zeroes and the coefficients in each case
(ii) x2 + 4x² + 5x – 2;(1, 1, 1)
Answers
Answered by
2
Answer:
(ii) x
3
−4x
2
+5x−2;2,1,1
p(x)=x
3
−4x
2
+5x−2 .... (1)
Zeroes for this polynomial are 2,1,1
Substitute x=2 in equation (1)
p(2)=2
3
−4×2
2
+5×2−2
=8−16+10−2=0
Substitute x=1 in equation (1)
p(1)=x
3
−4x
2
+5x−2
=1
3
−4(1)
2
+5(1)−2
=1−4+5−2=0
Therefore, 2,1,1 are the zeroes of the given polynomial.
Similar questions