Question

verify that weather -2 and 3 are zeros of the polynomial x²-x-6​

Answer 1

Answer:

-2

Step-by-step explanation:

substitute x=-2 and check first

[-2]^2-[-2]-6=0

4+2-6=0

0=0

so x=-2 is a zero

next substitute x=3

[3]^2-3-6=0

6-9=0

-3=0

which proves only -2 is the zero of the polynomial x^2-x-6

Answer 2

x²-x-6

By comparing to the general form, we get

a= 1, b= -1, c= -6

Let p(x)= x²-x-6

x²-x-6=0

x²-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3) (x+2)=0

x= 3 or x= -2

let α=3 or β=−2

α+β= -b/a. αβ= c/a

L.H.S= α+β L.H.S= αβ

= 3+(-2). = 3×(-2)

= 3-2. = -6

= 1. R.H.S= c/a

R.H.S= -b/a. = (-6)/1

= -(-1)/1. = -6

= 1/1

= 1

Therefore, L.H.S=R.H.S

Hence verify