verify that x^3+x^3=(x+y)(x^2-xy+y^2)
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x^3+y^3
=(x+y)^3-3xy(x+y)
=(x+y)[(x+y)^2-3xy)]
=(x+y)[x^2+y^2+2xy-3xy]
=(x+y)[x^2+y^2-xy]
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=(x+y)^3-3xy(x+y)
=(x+y)[(x+y)^2-3xy)]
=(x+y)[x^2+y^2+2xy-3xy]
=(x+y)[x^2+y^2-xy]
hope it helps.
please mark it as brainliest and follow me
yogendra1024:
plz mark it as brainliest and follow me
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x^3+y^3 =(x+y)^3-3xy(x+y) =(x+y)[(x+y)^2-3xy)] =(x+y)[x^2+y^2+2xy-3xy] =(x+y)[x^2+y^2-xy]
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