Question

verify the ( ab + bc ) ( ab - cb ) + ( bc + ca ) ( bc - ac ) + ( ca + ab ) ( ca - ba ) = 0​

Answer 1

Step-by-step explanation:

Taking L.H.S

( ab + bc ) ( ab - cb ) + ( bc + ca ) ( bc - ac ) + ( ca + ab ) ( ca - ba )

= (ab)² - ab²c + ab²c - (bc)² - ac²b + ac²b - (ac)² + (ac)² - ba²c + ba²c - (ab)²

= a²b² - a²b² - b²c² + b²c² - a²c² + a²c²

= 0 = R.H.S

L.H.S = R.H.S

Hence, proved...

hope it helps...