verify the following. (-32)×(-2)+(-1)=(-32)×(-2)+(-32)×(-1)
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(−32x)(−2−1)=(−32)(−2)+(−32x)(−1)
\rm Step\: 1: Simplify\: both\: sides\: of\: the\: equation.Step1:Simplifybothsidesoftheequation.
\sf (−32x)(−2−1)=(−32)(−2)+(−32x)(−1)(−32x)(−2−1)=(−32)(−2)+(−32x)(−1)
\sf 96x=64+32x96x=64+32x
\sf 96\:x=32\:x+6496x=32x+64
\rm Step \:2:\: Subtract\: 32x\: from \:both\: sides.Step2:Subtract32xfrombothsides.
\sf 96x−32x=32x+64−32x96x−32x=32x+64−32x
\sf 64x=6464x=64
\rm \:Step\: 3: \:Divide\: both\: sides\: by\: 64.Step3:Dividebothsidesby64.
64x \div 64 \: =646464x÷64=6464
x=1
\sf Answer:Answer:
\sf x=1x=1
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