verify the following results
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1.let the rational no.be 3 and irrational no.be √6
then sum=3+√6(irrational)
2.let the irrational no.be √2 and √3
product=√6(case 1)
let the irrational no.be √4
product=√4×√4=4(case 2)
in case 1 product is irrational but in case 2 the product is rational
then sum=3+√6(irrational)
2.let the irrational no.be √2 and √3
product=√6(case 1)
let the irrational no.be √4
product=√4×√4=4(case 2)
in case 1 product is irrational but in case 2 the product is rational
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